diff options
Diffstat (limited to 'vendor/github.com/btcsuite/btcd/btcec/field.go')
-rw-r--r-- | vendor/github.com/btcsuite/btcd/btcec/field.go | 203 |
1 files changed, 82 insertions, 121 deletions
diff --git a/vendor/github.com/btcsuite/btcd/btcec/field.go b/vendor/github.com/btcsuite/btcd/btcec/field.go index c2c6a645d..0f2be74c0 100644 --- a/vendor/github.com/btcsuite/btcd/btcec/field.go +++ b/vendor/github.com/btcsuite/btcd/btcec/field.go @@ -100,10 +100,6 @@ const ( // fieldPrimeWordOne is word one of the secp256k1 prime in the // internal field representation. It is used during negation. fieldPrimeWordOne = 0x3ffffbf - - // primeLowBits is the lower 2*fieldBase bits of the secp256k1 prime in - // its standard normalized form. It is used during modular reduction. - primeLowBits = 0xffffefffffc2f ) // fieldVal implements optimized fixed-precision arithmetic over the @@ -250,39 +246,15 @@ func (f *fieldVal) SetHex(hexString string) *fieldVal { // performs fast modular reduction over the secp256k1 prime by making use of the // special form of the prime. func (f *fieldVal) Normalize() *fieldVal { - // The field representation leaves 6 bits of overflow in each - // word so intermediate calculations can be performed without needing - // to propagate the carry to each higher word during the calculations. - // In order to normalize, first we need to "compact" the full 256-bit - // value to the right and treat the additional 64 leftmost bits as - // the magnitude. - m := f.n[0] - t0 := m & fieldBaseMask - m = (m >> fieldBase) + f.n[1] - t1 := m & fieldBaseMask - m = (m >> fieldBase) + f.n[2] - t2 := m & fieldBaseMask - m = (m >> fieldBase) + f.n[3] - t3 := m & fieldBaseMask - m = (m >> fieldBase) + f.n[4] - t4 := m & fieldBaseMask - m = (m >> fieldBase) + f.n[5] - t5 := m & fieldBaseMask - m = (m >> fieldBase) + f.n[6] - t6 := m & fieldBaseMask - m = (m >> fieldBase) + f.n[7] - t7 := m & fieldBaseMask - m = (m >> fieldBase) + f.n[8] - t8 := m & fieldBaseMask - m = (m >> fieldBase) + f.n[9] - t9 := m & fieldMSBMask - m = m >> fieldMSBBits - - // At this point, if the magnitude is greater than 0, the overall value - // is greater than the max possible 256-bit value. In particular, it is - // "how many times larger" than the max value it is. Since this field - // is doing arithmetic modulo the secp256k1 prime, we need to perform - // modular reduction over the prime. + // The field representation leaves 6 bits of overflow in each word so + // intermediate calculations can be performed without needing to + // propagate the carry to each higher word during the calculations. In + // order to normalize, we need to "compact" the full 256-bit value to + // the right while propagating any carries through to the high order + // word. + // + // Since this field is doing arithmetic modulo the secp256k1 prime, we + // also need to perform modular reduction over the prime. // // Per [HAC] section 14.3.4: Reduction method of moduli of special form, // when the modulus is of the special form m = b^t - c, highly efficient @@ -298,98 +270,87 @@ func (f *fieldVal) Normalize() *fieldVal { // // The algorithm presented in the referenced section typically repeats // until the quotient is zero. However, due to our field representation - // we already know at least how many times we would need to repeat as - // it's the value currently in m. Thus we can simply multiply the - // magnitude by the field representation of the prime and do a single - // iteration. Notice that nothing will be changed when the magnitude is - // zero, so we could skip this in that case, however always running - // regardless allows it to run in constant time. - r := t0 + m*977 - t0 = r & fieldBaseMask - r = (r >> fieldBase) + t1 + m*64 - t1 = r & fieldBaseMask - r = (r >> fieldBase) + t2 - t2 = r & fieldBaseMask - r = (r >> fieldBase) + t3 - t3 = r & fieldBaseMask - r = (r >> fieldBase) + t4 - t4 = r & fieldBaseMask - r = (r >> fieldBase) + t5 - t5 = r & fieldBaseMask - r = (r >> fieldBase) + t6 - t6 = r & fieldBaseMask - r = (r >> fieldBase) + t7 - t7 = r & fieldBaseMask - r = (r >> fieldBase) + t8 - t8 = r & fieldBaseMask - r = (r >> fieldBase) + t9 - t9 = r & fieldMSBMask - - // At this point, the result will be in the range 0 <= result <= - // prime + (2^64 - c). Therefore, one more subtraction of the prime - // might be needed if the current result is greater than or equal to the - // prime. The following does the final reduction in constant time. - // Note that the if/else here intentionally does the bitwise OR with - // zero even though it won't change the value to ensure constant time - // between the branches. - var mask int32 - lowBits := uint64(t1)<<fieldBase | uint64(t0) - if lowBits < primeLowBits { - mask |= -1 - } else { - mask |= 0 - } - if t2 < fieldBaseMask { - mask |= -1 - } else { - mask |= 0 - } - if t3 < fieldBaseMask { - mask |= -1 - } else { - mask |= 0 - } - if t4 < fieldBaseMask { - mask |= -1 - } else { - mask |= 0 - } - if t5 < fieldBaseMask { - mask |= -1 - } else { - mask |= 0 - } - if t6 < fieldBaseMask { - mask |= -1 + // we already know to within one reduction how many times we would need + // to repeat as it's the uppermost bits of the high order word. Thus we + // can simply multiply the magnitude by the field representation of the + // prime and do a single iteration. After this step there might be an + // additional carry to bit 256 (bit 22 of the high order word). + t9 := f.n[9] + m := t9 >> fieldMSBBits + t9 = t9 & fieldMSBMask + t0 := f.n[0] + m*977 + t1 := (t0 >> fieldBase) + f.n[1] + (m << 6) + t0 = t0 & fieldBaseMask + t2 := (t1 >> fieldBase) + f.n[2] + t1 = t1 & fieldBaseMask + t3 := (t2 >> fieldBase) + f.n[3] + t2 = t2 & fieldBaseMask + t4 := (t3 >> fieldBase) + f.n[4] + t3 = t3 & fieldBaseMask + t5 := (t4 >> fieldBase) + f.n[5] + t4 = t4 & fieldBaseMask + t6 := (t5 >> fieldBase) + f.n[6] + t5 = t5 & fieldBaseMask + t7 := (t6 >> fieldBase) + f.n[7] + t6 = t6 & fieldBaseMask + t8 := (t7 >> fieldBase) + f.n[8] + t7 = t7 & fieldBaseMask + t9 = (t8 >> fieldBase) + t9 + t8 = t8 & fieldBaseMask + + // At this point, the magnitude is guaranteed to be one, however, the + // value could still be greater than the prime if there was either a + // carry through to bit 256 (bit 22 of the higher order word) or the + // value is greater than or equal to the field characteristic. The + // following determines if either or these conditions are true and does + // the final reduction in constant time. + // + // Note that the if/else statements here intentionally do the bitwise + // operators even when it won't change the value to ensure constant time + // between the branches. Also note that 'm' will be zero when neither + // of the aforementioned conditions are true and the value will not be + // changed when 'm' is zero. + m = 1 + if t9 == fieldMSBMask { + m &= 1 } else { - mask |= 0 + m &= 0 } - if t7 < fieldBaseMask { - mask |= -1 + if t2&t3&t4&t5&t6&t7&t8 == fieldBaseMask { + m &= 1 } else { - mask |= 0 + m &= 0 } - if t8 < fieldBaseMask { - mask |= -1 + if ((t0+977)>>fieldBase + t1 + 64) > fieldBaseMask { + m &= 1 } else { - mask |= 0 + m &= 0 } - if t9 < fieldMSBMask { - mask |= -1 + if t9>>fieldMSBBits != 0 { + m |= 1 } else { - mask |= 0 + m |= 0 } - lowBits -= ^uint64(mask) & primeLowBits - t0 = uint32(lowBits & fieldBaseMask) - t1 = uint32((lowBits >> fieldBase) & fieldBaseMask) - t2 = t2 & uint32(mask) - t3 = t3 & uint32(mask) - t4 = t4 & uint32(mask) - t5 = t5 & uint32(mask) - t6 = t6 & uint32(mask) - t7 = t7 & uint32(mask) - t8 = t8 & uint32(mask) - t9 = t9 & uint32(mask) + t0 = t0 + m*977 + t1 = (t0 >> fieldBase) + t1 + (m << 6) + t0 = t0 & fieldBaseMask + t2 = (t1 >> fieldBase) + t2 + t1 = t1 & fieldBaseMask + t3 = (t2 >> fieldBase) + t3 + t2 = t2 & fieldBaseMask + t4 = (t3 >> fieldBase) + t4 + t3 = t3 & fieldBaseMask + t5 = (t4 >> fieldBase) + t5 + t4 = t4 & fieldBaseMask + t6 = (t5 >> fieldBase) + t6 + t5 = t5 & fieldBaseMask + t7 = (t6 >> fieldBase) + t7 + t6 = t6 & fieldBaseMask + t8 = (t7 >> fieldBase) + t8 + t7 = t7 & fieldBaseMask + t9 = (t8 >> fieldBase) + t9 + t8 = t8 & fieldBaseMask + t9 = t9 & fieldMSBMask // Remove potential multiple of 2^256. // Finally, set the normalized and reduced words. f.n[0] = t0 |