Eliminate `byte`-typedef and use `uint8_t` in all their places instead.

This change is made to (easily) be forward compatible with future C++
standards, in order to allow compiling the code with newer standards at
some point in the future.

* Removed the `using byte = uint8_t;` line from Common.h
* Mechanically change all uses of `byte` to `uint8_t`.

Tested with GCC 7.3 in C++11/14/17 modes :-)

1 files changed, 2 insertions, 2 deletions

diff --git a/test/ExecutionFramework.h b/test/ExecutionFramework.h
index 0b42f9d0..e275147b 100644
--- a/test/ExecutionFramework.h
+++ b/test/ExecutionFramework.h
@@ -147,11 +147,11 @@ public:
 
 	static std::pair<bool, std::string> compareAndCreateMessage(bytes const& _result, bytes const& _expectation);
 
-	static bytes encode(bool _value) { return encode(byte(_value)); }
+	static bytes encode(bool _value) { return encode(uint8_t(_value)); }
 	static bytes encode(int _value) { return encode(u256(_value)); }
 	static bytes encode(size_t _value) { return encode(u256(_value)); }
 	static bytes encode(char const* _value) { return encode(std::string(_value)); }
-	static bytes encode(byte _value) { return bytes(31, 0) + bytes{_value}; }
+	static bytes encode(uint8_t _value) { return bytes(31, 0) + bytes{_value}; }
 	static bytes encode(u256 const& _value) { return toBigEndian(_value); }
 	/// @returns the fixed-point encoding of a rational number with a given
 	/// number of fractional bits.